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KB Term:  Term intersection
English Word: 

  QuintaryPredicate

Sigma KEE - QuintaryPredicate
QuintaryPredicate(quintary predicate)

appearance as argument number 1
-------------------------


s__documentation(s__QuintaryPredicate,s__ChineseLanguage,'"这是一个需要五个参数的 Predicate Class。"')

chinese_format.kif 2017-2018
s__documentation(s__QuintaryPredicate,s__EnglishLanguage,'"The Class of Predicates that require five arguments."')

Merge.kif 3438-3439
s__subclass(s__QuintaryPredicate,s__InheritableRelation)

s__instance(s__InheritableRelation,s__Class)

s__instance(s__QuintaryPredicate,s__Class)

Merge.kif 3436-3436 Quintary predicate is a subclass of inheritable relation
s__subclass(s__QuintaryPredicate,s__Predicate)

s__instance(s__Predicate,s__Class)

s__instance(s__QuintaryPredicate,s__Class)

Merge.kif 3434-3434 Quintary predicate is a subclass of predicate
s__subclass(s__QuintaryPredicate,s__QuintaryRelation)

s__instance(s__QuintaryRelation,s__Class)

s__instance(s__QuintaryPredicate,s__Class)

Merge.kif 3435-3435 Quintary predicate is a subclass of quintary relation

appearance as argument number 2
-------------------------


s__format(s__ChineseLanguage,s__QuintaryPredicate,'"%1 %n 是 对于 %3 和 %4 跟 %5 的 quintary 谓语"')

domainEnglishFormat.kif 2091-2091
s__format(s__ChineseTraditionalLanguage,s__QuintaryPredicate,'"%1 %n 是 對於 %3 和 %4 跟 %5 的 quintary 謂語"')

domainEnglishFormat.kif 2090-2090
s__format(s__EnglishLanguage,s__QuintaryPredicate,'"%1 is %n quintary predicate %2 for %3 with %4 and %5"')

domainEnglishFormat.kif 2089-2089
s__instance(s__componentDataID__m,s__QuintaryPredicate)

s__instance(s__QuintaryPredicate,s__Class)

QoSontology.kif 894-894 component data ID is an instance of quintary predicate
s__instance(s__playsRoleInEventOfType__m,s__QuintaryPredicate)

s__instance(s__QuintaryPredicate,s__Class)

Mid-level-ontology.kif 22546-22546 plays role in event of type is an instance of quintary predicate
s__termFormat(s__ChineseLanguage,s__QuintaryPredicate,'"五元谓语"')

chinese_format.kif 929-929
s__termFormat(s__EnglishLanguage,s__QuintaryPredicate,'"quintary predicate"')

english_format.kif 1065-1065

antecedent
-------------------------


( ! [V__REL] :
   ((s__instance(V__REL,s__QuintaryPredicate) =>
       (s__valence(V__REL,n__5)))
   )
)

Merge.kif 3441-3443


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