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KB:
Language:
Formal Language:
|
| componentDataID |
| appearance as argument number 1 |
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|
| appearance as argument number 2 |
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| (format EnglishLanguage componentDataID "%1 %n{doesn't} component dataID %2 for %3 with %4 and %5") | domainEnglishFormat.kif 506-506 | |
| (format ChineseTraditionalLanguage componentDataID "%1 %n{不是} component 資料ID 對於 %3 跟 %4 和 %5 在一起") | domainEnglishFormat.kif 507-507 | |
| (format ChineseLanguage componentDataID "%1 %n{不是} component 资料ID 对于 %3 跟 %4 和 %5 在一起") | domainEnglishFormat.kif 508-508 | |
| (termFormat EnglishLanguage componentDataID "component data ID") | domainEnglishFormat.kif 16206-16206 | |
| (termFormat ChineseTraditionalLanguage componentDataID "組件數據ID") | domainEnglishFormat.kif 16207-16207 | |
| (termFormat ChineseLanguage componentDataID "组件数据ID") | domainEnglishFormat.kif 16208-16208 |
| antecedent |
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|
| (=> (componentDataID ?Time ?Component ?Instance ?Unit ?Number) (instance ?Instance ?Component)) |
QoSontology.kif 1003-1005 | If X component dataID Y for Z with W and V, then Z is an instance of Y |
| (=> (componentDataID ?Time ?Component ?Instance ?Unit ?Number) (unitMeasuringPerformance ?Instance ?Unit)) |
QoSontology.kif 1007-1009 | If X component dataID Y for Z with W and V, then W is an unit measuring performance of Z |
| (=> (componentDataID ?Time ?Component ?Instance ?Unit ?Number) (refers ?Number ?Instance)) |
QoSontology.kif 1011-1013 | If X component dataID Y for Z with W and V, then V includes a reference to Z |
| (=> (and (monitorComponentData ?Time1 ?ID ?Number) (componentDataID ?Time2 ?Component ?Instance ?Unit ?ID)) (exists (?Event) (and (instance ?Event MeasuringPerformance) (unitMeasuringPerformance ?Instance ?Unit) (time ?Event ?Time1) (performanceResult ?Event ?Instance ?Number)))) |
QoSontology.kif 1051-1060 | If X is monitor component data Y for Z and W component dataID V for U with T and Y, then there exists S such that S is an instance of measuring performance, T is an unit measuring performance of U, S exists during X, and S is performance result U for Z |