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Formal Language:
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| LiftFn |
| appearance as argument number 1 |
|
| (instance LiftFn BinaryFunction) | UXExperimentalTerms.kif 4546-4546 | Lift is an instance of binary function |
| (domain LiftFn 1 Quantity) | UXExperimentalTerms.kif 4548-4548 | The number 1 argument of lift is an instance of quantity |
| (domain LiftFn 2 Quantity) | UXExperimentalTerms.kif 4550-4550 | The number 2 argument of lift is an instance of quantity |
| (range LiftFn RealNumber) | UXExperimentalTerms.kif 4552-4552 | The range of lift is an instance of real number |
| (documentation LiftFn EnglishLanguage "(LiftFn ?QUANTITY1 ?QUANTITY2) returns the lift of the quantities. i.e. (?QUANTITY1 - ?QUANTITY2)/ (?QUANTITY2). In an experiment ?QUANTITY2 is the Quantity that represents the control group.") | UXExperimentalTerms.kif 4556-4558 | The range of lift is an instance of real number |
| appearance as argument number 2 |
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| (termFormat EnglishLanguage LiftFn "lift") | UXExperimentalTerms.kif 4554-4554 | |
| (format EnglishLanguage LiftFn "the financial improvement percentage of %1 over %2") | domainEnglishFormat.kif 3754-3754 | |
| (format ChineseTraditionalLanguage LiftFn "%1 的 financial improvement 百分比 在 %2 之上") | domainEnglishFormat.kif 3755-3755 | |
| (format ChineseLanguage LiftFn "%1 的 financial improvement 百分比 在 %2 之上") | domainEnglishFormat.kif 3756-3756 |
| consequent |
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| (=> (and (instance ?QUANTITY1 Quantity) (instance ?QUANTITY2 Quantity)) (equal (LiftFn ?QUANTITY1 ?QUANTITY2) (DivisionFn (SubtractionFn ?QUANTITY1 ?QUANTITY2) ?QUANTITY2))) |
UXExperimentalTerms.kif 4560-4568 | If X is an instance of quantity and Y is an instance of quantity, then equal the financial improvement percentage of X over Y and (X and Y) and Y |
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