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KB Term:  Term intersection
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Sigma KEE - CreditCardAccount
CreditCardAccount(credit card account)

appearance as argument number 1
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(subclass CreditCardAccount CreditAccount) FinancialOntology.kif 1273-1273 Credit card account is a subclass of credit account
(documentation CreditCardAccount EnglishLanguage "A type of CreditAccount which uses a CreditCard for FinancialTransactions.") FinancialOntology.kif 1274-1275 Credit card account is a subclass of credit account
(externalImage CreditCardAccount "http://upload.wikimedia.org/wikipedia/ commons/ 4/ 4f/ Credit_cards.jpg") pictureList.kif 9131-9131 Credit card account is a subclass of credit account

appearance as argument number 2
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(termFormat EnglishLanguage CreditCardAccount "credit card account") domainEnglishFormat.kif 17754-17754
(termFormat ChineseTraditionalLanguage CreditCardAccount "信用卡帳戶") domainEnglishFormat.kif 17755-17755
(termFormat ChineseLanguage CreditCardAccount "信用卡帐户") domainEnglishFormat.kif 17756-17756

antecedent
-------------------------


(=>
    (and
        (instance ?Account CreditCardAccount)
        (instance ?Transaction FinancialTransaction)
        (origin ?Transaction
            (CurrencyFn ?Account)))
    (exists (?Card)
        (and
            (instance ?Card CreditCard)
            (instrument ?Transaction ?Card))))
FinancialOntology.kif 1277-1285 If X is an instance of credit card account, Y is an instance of financial transaction, and Y originates at the currency of X, then there exists Z such that Z is an instance of credit card and Z is an instrument for Y

consequent
-------------------------


(=>
    (and
        (instance ?Card CreditCard)
        (possesses ?Agent ?Card))
    (exists (?Account)
        (and
            (instance ?Account CreditCardAccount)
            (cardAccount ?Card ?Account)
            (accountHolder ?Account ?Agent))))
FinancialOntology.kif 220-228 If X is an instance of credit card and Y possesses X, then there exists Z such that Z is an instance of credit card account, Z is a card account of X, and Y holds account Z


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